- 12 g
^{12}C

Solution:**the number of atoms in exactly 12 grams of isotopically pure**^{12}C,

is equal to 6.02 × 10^{23}carbon atoms. - 1 mol C
_{4}H_{4}

Solution:**1 mol C**_{4}H_{4}= 6.02 × 10^{23}molecules of C_{4}H_{4}

which means there 4 × 6.02 × 10^{23}molecules of C = 24 × 10^{23}molecules of C - 9 × 10
^{23}molecules of CO_{2}

Solution:**Same number which is 9 × 10**^{23}molecules of CO_{2}

12 g

Date of last modification: Summer , 2019